jaydenwiggins00
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Question 1 of 10
2 Points
The circle below is centered at the point (-3, 4) and has a radius of length 3.
What is its equation?
O
O A. (x-4)2 + (y + 3)2 =
32
O
O B. (x+4)2 + (x-3)2 =
O C. (x+3)2 + (x-4)2 = 9
O D. (x - 3)2 + (y + 4)2 = 9
SUBMIT

Respuesta :

Answer:

C.  (x + 3)^2 + (y - 4)^2 = 9.

Step-by-step explanation:

The general form of a circle with center (a,b) and radius r is:

(x - a)^2 + (y - b)^2 = r^2

So substituting the given values the equation of our circle is:

(x - (-3)^2 + (y - 4)^2 = 3^2

(x + 3)^2 + (y - 4)^2 = 9.

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