Respuesta :
The options are: -2-4=x₁ and 15 + y₁=16.
Step-by-step explanation:
The formula for midpoint of a segment AB,where A(x,y) and B(x₁y₁) is given by;
(x+x₁)/2 , (y+y₁)/2
Given in question segment JK as J(4,-15) , midpoint of JK(-1,8) and K(x₁,y₁) then to find K(x₁,y₁) , apply the formula for mid point ;
(x+x₁)/2 , (y+y₁)/2
(-1,8) =(x₁+4)/2 , (y₁+ -15)/2
-1=(x₁+4)/2 ------------------multiply both sides by 2
-2=(x₁+4)
-2=x₁ +4 ---------------------collect like terms
-2-4=x₁
-6=x₁-------------------------The equation should be: -2-4=x₁
and
8= (y₁+ -15)/2
16= (y₁+ -15)
16=y₁+ -15
16+15=y₁
31=y₁------------------------15 + y₁=16
Checking the answers
Segment JK where J(4,-15) and K(-6,31) then the midpoint will be :
(x+x₁)/2 , (y+y₁)/2
(4+-6)/2 ,(-15+31)
(-2)/2 ,(16)/2
(-1,8) ---------midpoint of segment JK
Learn More
Midpoint of a segment formula : https://brainly.com/question/10424143
Finding midpoint of a segment : https://brainly.com/question/7729444
Keyword : midpoint, endpoint,coordinates
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Answer:(1) -15+y1=16 and x2= 6 which is not present among the options
Step-by-step explanation:
We must first note that the midpoint of a line is given by,
x=(x1+x2)/2
and
y=( y1+y2)/2.
Since, the midpoint and point, J are on the same line, however , doing that is going to make the problem prove difficult,
Therefore,
We must note that the x coordinate of point K is just as far from the midpoint of the line as the x coordinate of J.
Therefore, 2x= Xj+Xk
Xk= 2(-1) - 4
Xk=-6
The same goes for Yk,
We must note that the y coordinate of point K is just as far from the midpoint of the line as the y coordinate of J.
Therefore, 2Y= Yj+Yk
Yk=2(8)-(-15)
Yk= 31
Therefore, the equation which satisfies Xk= 2, is the equation;
Probably, -(2+4)=X1
Which is not among the options
The equation which satisfies Yk=311, is the equation;
-15+y1=16.