Answer:
The volume occupied by given molecules of carbon dioxide at STP is 55.86 L.
Explanation:
[tex]N=n\times N_A[/tex]
Where:
N = Number of particles / atoms/ molecules
n = Number of moles
[tex]N_A=6.022\times 10^{23} mol^{-1}[/tex] = Avogadro's number
We have:
N = [tex]1.5\times 10^{24} [/tex]
n =?
[tex]n=\frac{N}{N_A}=\frac{1.5\times 10^{24}}{6.022\times 10^{23} mol^{-1}}[/tex]
n = 2.4909 moles
Using ideal gas equation:
PV = nRT
where,
P = Pressure of carbon dioxide gas = [tex]1 atm[/tex] (at STP)
V = Volume of carbon dioxide gas = ?
n = number of moles of carbon dioxide gas =2.4909 mol
R = Gas constant = 0.0821 L.atm/mol.K
T = Temperature of carbon dioxide gas = 273.15 K (at STP)
Putting values in above equation, we get:
[tex]V=\frac{2.4909 mol\times 0.0821 atm L/mol K\times 273.15 K}{1 atm}[/tex]
V = 55.86 L
The volume occupied by given molecules of carbon dioxide at STP is 55.86 L.
