Answer:
For the given explanation we see that two life times are not independent
Step-by-step explanation:
probability for X (for x≥ 0)
[tex]\int\limits^\infty_0 {xe^-^x^(^1^+^y^)} \, dy[/tex]
[tex]-e^-^x\int\limits^\infty_0 {de^-^x^y} \,[/tex]
e⁻ˣ
Probability for X exceed 3
= [tex]\int\limits^\infty_3 {f(x)dx[/tex]
= [tex]\int\limits^\infty_3 {e^-^3 dx [/tex]
= [tex]e^-^3[/tex]
probabilty for y≥ 0 is
[tex]\int\limits^\infty_0 {xe^-^x^(^1^+^y^)} \, dx \\[/tex]
[tex]\int\limits^\infty_0{-x/1+yd(e^-^x^(^1^+^y^))} \, =1/(1+y)² \\[/tex]
