Answer:
LENGTH= 16 and WIDTH= 13
Step-by-step explanation:
Let the length of rectangle be l
and, its width be b
So, according to question
l = b+3
and,
2(l+b)=58
[We know that perimeter of a rectangle= 2(l+b)]
Substituting l=b+3 in 2nd equation
2(b+3+b)=58
2b+3=58/2
2b+3=29
2b=29-3=26
b=26/2
b= 13
So, l=b+3
l= 13+3=16
Hence the dimensions are 16 and 13
HOPE IT IS USEFUL
Width of the rectangle = 13 cm
Length of the rectangle =16cm
Given :
the length of a rectangle is 3 more than its width. the perimeter of the rectangle is 58cm.
Let 'w' be the width of the rectangle
Length of rectangle is 3 more than is width
length = w+3
Perimeter of rectangle formula is
[tex]P= 2(length )+2(width )\\P=2L+2w\\P=2(w+3)+2w\\P=2w+6+2w\\P=4w+6[/tex]
Now we replace perimeter by 58 and solve for w
[tex]P=4w+6\\58=4w+6\\58-6=4w\\52=4w\\w=13[/tex]
Width of the rectangle = 13 cm
Length of the rectangle = w+3=13+3=16
Learn more : brainly.com/question/14711527
