Respuesta :

Answer:

The Answer is last option

[tex]\left[\begin{array}{ccc}x_{1}\\x_{2}\\\end{array}\right]=\left[\begin{array}{ccc}0.5&-3\\0&1\\\end{array}\right]\left[\begin{array}{ccc}2\\-3\\\end{array}\right][/tex]

Step-by-step explanation:

The Answer is last option

[tex]\left[\begin{array}{ccc}x_{1}\\x_{2}\\\end{array}\right]=\left[\begin{array}{ccc}0.5&-3\\0&1\\\end{array}\right]\left[\begin{array}{ccc}2\\-3\\\end{array}\right][/tex]

Write The Given Matrix in

AX= B

Now Pre multiplying by [tex]A^{-1}[/tex] we get

[tex]A^{-1}AX=A^{-1}B\\ \\We\ know\\A^{-1}A = I\ and\ IX = X\\\\\therefore X = A^{-1}B\\\\\therefore \left[\begin{array}{ccc}x_{1}\\x_{2}\\\end{array}\right]=\left[\begin{array}{ccc}0.5&-3\\0&1\\\end{array}\right]\left[\begin{array}{ccc}2\\-3\\\end{array}\right][/tex]

Here,

[tex]A^{-1}=\left[\begin{array}{ccc}0.5&-3\\0&1\end{array}\right]\\\\X=\left[\begin{array}{ccc}x_{1}\\ x_{2}\end{array}\right] \\\\B=\left[\begin{array}{ccc}2\\-3\end{array}\right][/tex]

19090

Answer:

i think it is d on edge

Step-by-step explanation: