Answer:
10.82 m
Step-by-step explanation:
Length of ladder (L) = 15.5 m
Degree with the horizontal (θ) = 44°15'=44.25°
This problem can be interpreted as a right triangle with L being the hypotenuse. The distance 'd' the ladder goes up the wall is the side opposite to the given angle. Therefore, the sine property can be used to find 'd':
[tex]sin(\theta) = \frac{opposite}{hypotenuse}\\sin(44.25)=\frac{d}{15.5}\\d= 10.82\ m[/tex]
The distance that the ladder goes up the wall is roughly 10.82 m.
