Value of the pursue in cents: [tex]131p+175[/tex]
Step-by-step explanation:
Let's call:
[tex]p[/tex] = number of pennies
The problem tells us that the pursue contains twice as many nickels as pennies, so the number of nickels is
[tex]n=2p[/tex]
Also, the pursue contains five more dimes than nickels, so the number of dimes is
[tex]d=n+5=2p+5[/tex]
And finally, the pursue contains as many quarters as dimes and nickels combained, so the number of quarters is
[tex]q=d+n=(2p+5)+2p=4p+5[/tex]
The value of each type of coin is:
Penny: 1 cent
Nickel: 5 cents
Dime: 10 cents
Quarter: 25 cents
So, the total value of the pursue in cents is:
[tex]1p+5n+10d+25q[/tex]
And substituting,
[tex]=p+5(2p)+10(2p+5)+25(4p+5)=\\p+10p+20p+50+100p+125=\\131p+175[/tex]
So, this is the value of the change in the pursue in cents.
Learn more about expressions:
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