Respuesta :
D. In all four types of broth.
Explanation:
The plasmid will provide the origin of replication to the gene in question as it is a self-replicating body in the bacterial cell. The recombinant DNA technology is used for the purpose but here the plasmid itself has resistant gene for ampicillin and tetracycline.
The plasmid minus the eukaryotic gene can survive on all the media with or without antibiotics as it is resistant to both. In normal media, it will also survive and grow. So, colonies are seen after incubation in all the four media.
The plasmid is ampicillin resistant so grow in all the media.
The plasmid is also tetracycline-resistant so would grow in media having broth of tetracycline or both ampicillin and tetracycline.
Bacteria that contain the plasmid, but not the eukaryotic gene, would grow in all four types of broth (Option D).
- A plasmid is a bacterial fragment of DNA physically separated from the bacterial chromosome and thus replicates independently from it.
- Moreover, a ligase is an enzyme that enables the ligation of different DNA strands by catalyzing the formation of phosphodiester bonds between nucleotides.
- In this case, the bacterial plasmid contains two genes that confer resistance to the antibiotics ampicillin and tetracycline.
In conclusion, bacteria that contain the plasmid, but not the eukaryotic gene, would grow in all four types of broth (Option D).
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