Answer:
The answer to your question is C₃H₇
Explanation:
Data
mass of CO₂ = 3.447 g
mass of H₂ = 1.647 g
Empirical formula = ?
Process
1.- Write the chemical reaction
CxHy + O₂ ⇒ CO₂ + H₂O
2.- Calculate the mass and moles of carbon
44 g of CO₂ --------------- 12 g of C
3.447 g of CO₂ --------- x
x = (3.447 x 12) / 44
x = 0.94 g of C
12 g of C ----------------- 1 mol
0.94 g of C ------------- x
x = 0.0783 moles of C
3.- Calculate the grams and moles of H
18 g of H₂O -------------- 2 g of H
1.647 g of H₂O --------- x
x = (1.647 x 2)/18
x = 0.183 g of H
1 g of H ------------------ 1 mol
0.183 g ------------------ x
x = (0.183 x 1)/1
x = 0.183 mol of H
4.- Divide by the lowest number of moles
Carbon = 0.0783 /0.0783 = 1
Hydrogen = 0.183 / 0.0783 =2.3
5.- Write the empirical formula
C₁H₂.₃ = 3C₁H₂.₃ = C₃H₇
