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Answer:
The number of bags of chips sold was 20 and the number of fruit snacks sold was 5
Step-by-step explanation:
Let
x ---> the number of bags of chips sold
y ---> the number of fruit snacks sold
we know that
Penelope made $42.50
so
[tex]1.75x+1.50y=42.50[/tex] ----> equation A
Penelope sold 15 more bags of chips than fruit snacks.
[tex]x=y+15[/tex] ----> equation B
substitute equation B in equation A
[tex]1.75(y+15)+1.50y=42.50[/tex]
solve for y
[tex]1.75y+26.25+1.50y=42.50\\3.25y=16.25\\y=5[/tex]
Find the value of x
[tex]x=5+15=20[/tex]
therefore
The number of bags of chips sold was 20 and the number of fruit snacks sold was 5
The number of bags of chips sold was 20 and the number of fruit snacks sold was 5.
Given that,
- The price of each bag of chips is $1.75 and the price of each fruit snack is $1.50.
- Yesterday Penelope made $42.50 and sold 15 more bags of chips than fruit snacks.
- Here we assume x be the number of bags of chips sold and y be the number of fruit snacks sold.
Based on the above information, the calculation is as follows:
1.75x + 1.50y = 42.50
x = y + 15
Now put x value to the above equation
1.75(y + 15) + 1.50y = 42.50
1.75y + 26.25 + 1.50y = 42.50
3.25y = 16.25
y = 5
So, x = 5 + 15 = 20
Learn more: brainly.com/question/17429689