An egg is thrown nearly vertically upward from a point near the cornice of a tall building. It just misses the cornice on the way down and passes a point a distance 36.0 m below its starting point at a time 5.00 s after it leaves the thrower's hand. Air resistance may be ignored.

Asked:
what is the initial speed?
How High does it move above the starting point?

Respuesta :

Answer:

17.325 m/s

15.2984518349 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s² = a

[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow u=\dfrac{s-\frac{1}{2}at^2}{t}\\\Rightarrow u=\dfrac{-36-\frac{1}{2}\times -9.81\times 5^2}{5}\\\Rightarrow u=17.325\ m/s[/tex]

The initial velocity of the egg is 17.325 m/s

[tex]v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-17.325^2}{2\times -9.81}\\\Rightarrow s=15.2984518349\ m[/tex]

The maximum height is 15.2984518349 m above the starting point