Answer:
Explanation:
from Fourier law,
q = -K(∆T/L)
but q = Q/A,
hence,
K = (QL)/(AΔT)
Q = Joules/s = ML²/T³
L = L
A = L²
∆T = Kelvin = K
since K = (QL)/(AΔT)
substitute the fundamental units into the above equation we have
K = (ML²/T³)(L)/(L²K) = ML³/T³L²K = ML/T³K
the thermal conductivity, K dimensionality = ML/T³K
or mass lenght per cube unit seconds per Kelvin
