calculate the kinetic energy in j/mol of particles with mass 32.5 g/mol with an average speed of 491 m/sec.

Respuesta :

Answer:

The kinetic energy is 3917.57J/mol

Explanation:

The kinetic energy (K.E.) of a body is the energy possess by the body while on motion

K.E is given by 1/2xM[tex]V^{2}[/tex]

Where M= mass in Kg = 32.5/1000

M= 0.0325kg

V = velocity in m/s = 491m/s

Substituting these values in the formual

K.E = 1/2MV^{2}

K. E = ½ x 0.0325kgx 491 m/s x 491 m/s

K.E = 3917.57kg[tex]m^{2}[/tex]/ [tex]Sec^{2}[/tex]/ mol

But  kg[tex]m^{2}[/tex]/ [tex]Sec^{2}[/tex] = Joule

Thus kinetic energy, K.E = 3917.57kg[tex]m^{2}[/tex]/ [tex]Sec^{2}[/tex]/ mol