Magnitude of the force of tension: 139 N
Explanation:
The surface of the ramp here is assumed to be the positive x-direction.
To solve this problem and find the magnitude of the force of tension, we have to analyze only the situation along the x-direction, since the force of tension lie in this direction.
There are three forces acting along the x-direction:
- The force of tension, [tex]F_T[/tex], acting up along the plane
- The force of friction, [tex]F_f=14.8 N[/tex], acting down along the plane
- The component of the weight in the x-direction, [tex]F_{gx}[/tex], acting down along the plane
We know that the magnitude of the weight is
[tex]F_g=70.0 N[/tex]
So its x-component is
[tex]F_{gx}=F_g sin \theta =(70.0)(sin 22^{\circ})=26.2 N[/tex]
The net force along the x-direction can be written as
[tex]F_x = F_T-F_f-F_{gx}[/tex]
And therefore, since the net force is 98 N, we can find the magnitude of the force of tension:
[tex]F_T=F_x+F_f+F_{gx}=98+14.8+26.2=139 N[/tex]
Learn more about inclined planes:
brainly.com/question/5884009
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