Answer:
[tex]\frac{dN}{dt}=2.5 g/day[/tex]
Step-by-step explanation:
The logistic model equation is a differential equation, given by:
[tex]\frac{dN}{dt}=r\left(\frac{K-N}{K} \right)N[/tex]
Now, in this particularly model the optimum yield is at K/2. This value is the population here, so N=K/2.
[tex]\frac{dN}{dt}=0.1\left(\frac{100-(100/2)}{100} \right)(100/2)[/tex]
[tex]\frac{dN}{dt}=2.5 g/day[/tex]
Have a nice day!