Respuesta :
Answer:
t=2s
Explanation:
The definition of power is:
[tex]P=\frac{W}{t}[/tex]
And the work-energy theorem states that:
[tex]W=\Delta K[/tex]
Since the movement starts from rest, we have that:
[tex]\Delta K=\frac{mv_f^2}{2}-\frac{mv_0^2}{2}=\frac{mv_f^2}{2}[/tex]
And putting all together:
[tex]P=\frac{mv_f^2}{2t}[/tex]
Since we want the time taken:
[tex]t=\frac{mv_f^2}{2P}[/tex]
Which for our values is:
[tex]t=\frac{(120kg)(5m/s)^2}{2(746W)}=2s[/tex]
Answer:
time = 2s
Explanation:
Power is:
[tex]P=\frac{W}{t}[/tex]
work-energy theorem states that:
[tex]W=\Delta K[/tex]
Since the movement starts from rest, we have that:
[tex]\Delta K=\frac{mv_f^2}{2}-\frac{mv_0^2}{2}=\frac{mv_f^2}{2}[/tex]
And putting all together:
[tex]P=\frac{mv_f^2}{2t}[/tex]
the time taken:
[tex]t=\frac{mv_f^2}{2P}[/tex]
Which for our values is:
[tex]t=\frac{(120kg)(5m/s)^2}{2(746W)}\\= 2s[/tex]