Respuesta :
Answer:
The electric field is [tex]8.75 \times 10^{6}~v~m^{-1}[/tex] and the ditection is from outer to inner side of the membrane.
Explanation:
We know the electric field ([tex]\vec{E}[/tex]) is given by [tex]\vec{E} = - \nabla V[/tex], 'V' being the potential.
In 1-D, it can be written as
[tex]E=\dfrac{V}{d}[/tex]
where 'd' is the separation of space in between the potential difference is created.
Given, [tex]V = 0.070~V~[/tex] and the thickness of the cell membrane is [tex]d = 8.0 \times 10^{-9}~m[/tex].
Therefore the created electric field through the cell membrane is
[tex]E = \dfrac{0.07~V}{8 \times 10^{-9}~m} = 8.75 \times 10^{6}~m~s^{-1}[/tex]
