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Mitchel owns a livestock trailer that can hold a maximum of 5,000 pounds. The average weight of each goat is 90 pounds, and the average weight of each calf is 360 pounds. Mitchel would like to know how many goats and calves he can transport in a single trip.

The inequality that represents this situation is graphed here.

Mitchel owns a livestock trailer that can hold a maximum of 5000 pounds The average weight of each goat is 90 pounds and the average weight of each calf is 360 class=

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amosarteta

The number of cows and calves Mitchel can transport is determined by the inequity 90g+360c \leq 5000

varshamittal029

Option A) satisfies the condition, and 42 goats and 2 calves can be taken in the livestock trailer in one trip.

What is inequality?

In an inequality, two values are compared to see if one is less than the other.

How to solve the problem?

Let 't' be the number of goats that he will take in one trip and 's' be the number of calves he would take. Then to hold the livestock in the trailer we must have

90t+360s<5000

We would just check which option satisfies the inequality to reach to our answer.

A) 90×42+360×2=4500<5000

B) 90×30+360×8=5580>5000

C) 90×24+360×10=5760>5000

D) 90×50+360×4=5940>5000

Hence, we come to the conclusion that option A) satisfies the condition, and 42 goats and 2 calves can be taken in the livestock trailer in one trip.

To learn more about inequality visit- https://brainly.com/question/20383699?referrer=searchResults

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