Answer:
The correct option is option (c)
Therefore amplitude = 4, period= π and [tex]\textrm{phase shift}=\frac{-\pi}{2}[/tex]
Step-by-step explanation:
Amplitude: The amplitude of a wave is a maximum displacement of a particle from its rest position
Period: The ratio of wavelength to the velocity.
Phase shift: The phase shift represents the amount a wave has shifted horizontally from the the usual position.
The equation of a wave is
f(x) = a sin(bx - c)+d
Where
amplitude = |a|
[tex]Period= \frac{2\pi}{|b|}[/tex]
[tex]\textrm{phase shift} = \frac{c}{b}[/tex]
Given equation of wave is
f(x) = -4sin (2x + π) -3
Here a=-4, b=2, c = -π, d = -3
Amplitude = |-4| = 4
[tex]Period = \frac {2 \pi}{|2|}= \pi[/tex]
[tex]\textrm{phase shift}=\frac{-\pi}{2}[/tex]
Therefore amplitude = 4, period= π and [tex]\textrm{phase shift}=\frac{-\pi}{2}[/tex]
Answer:
c. Amplitude = 4; period = π; phase shift: x equals negative pi over two
Step-by-step explanation:
