Answer:
The change in momentum of the ball is 4.52 kg-m/s.
Explanation:
Given that,
Mass of the ball, m = 0.62 kg
Initial speed of the ball, u = 4.7 m/s
The ball rebounds with a speed of 2.6 m/s, v = -2.6 m/s
We need to find the magnitude of the change in linear momentum of the ball. We know that the linear momentum is given by :
p = mv
So, the change in momentum is :
[tex]\Delta p=m(v-u)\\\\\Delta p=0.62\times ((-2.6)-4.7)\\\\\Delta p=-4.52\ kg-m/s\\\\|\Delta p|=4.52\ kg-m/s[/tex]
So, the change in momentum of the ball is 4.52 kg-m/s. Hence, this is the required solution.
