Answer:
[tex] P(X>300)[/tex]
And we can find this probability with the complement rule:
[tex] P(X>300)= 1-P(X<300) = 1-\frac{300-284.7}{310.6-284.7} =0.4093[/tex]
Step-by-step explanation:
For this case we define the random variable X ="driving distance for the top 100 golfers on the PGA tour" and we know that:
[tex] X \sim Unif (a=284.7, b=310.6)[/tex]
And for this case the probability density function is given by:
[tex] f(x) =\frac{1}{310.6 -284.7} =0.0386 , 284.7 \leq X \leq 310.6 [/tex]
And the cumulative distribution function is given by:
[tex] F(x) =\frac{x-284.7}{310.6-284.7} , 284.7 \leq X \leq 310.6 [/tex]
And we want to find this probability:
[tex] P(X>300)[/tex]
And we can find this probability with the complement rule:
[tex] P(X>300)= 1-P(X<300) = 1-\frac{300-284.7}{310.6-284.7} =0.4093[/tex]
