could u plz help I don't know this
at all
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The area of the given figure is 56 sq cm
Step-by-step explanation:
Given,
The figure consists of 5 different diagrams: 4 triangles and a square
Each side of square = 4 cm
Height(h) of the triangle = 5 cm
Base(b) of the triangle = 4 cm
To find the area of the given figure
Formula
Area of square = side × side sq cm
Area of triangle = [tex]\frac{1}{2}[/tex]×base × height
So, area of square = 4 ×4 sq cm = 16 sq cm
Area of triangle = [tex]\frac{1}{2}[/tex]×4×5 sq cm = 10 sq cm
The area of 4 triangles = 10×4 sq cm = 40 sq cm
Hence the area of the given diagram = 40 + 16 sq cm = 56 sq cm