Respuesta :

amna04352

Answer:

ln2

Step-by-step explanation:

n --> infinity

Integral of 1/N as N varies from n+1 to 2n

Integral of 1/N = ln(N)

Upper limit - lower limit

ln(2n) - ln(n + 1)

ln[2n/(n + 1)]

ln[2/(1 + 1/n)]

As n --> infinity,

1/n --> 0

ln[2/(1 + 1/n)] --> ln2

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