The given line passes through the points (0 - 3) and (2,3)

What is the equation, in point-slope form of the line the
parallel to the given line and passes through the point -1,-1)?
O
+1
-3(x + 1)
Oy+1. -*(x+1)
Oy+2-5-(x+1)
Oy+1=3(x+1)
(0.
3)

Respuesta :

Answer:

  y+1=3(x+1)

Step-by-step explanation:

The slope of the given line is ...

  m = (y2 -y1)/(x2 -x1)

  m = (3 -(-3))/(2 -0) = 6/2 = 3

The point-slope form of the equation of a line with slope m through point (h, k) is ...

  y -k = m(x -h)

Whe have m=3, h=-1, k=-1, so the equation is ...

  y +1 = 3(x +1)

The equation, in the point-slope form of the line the parallel to the given line and passes through the point (-1,-1) is y + 1  = 3(x+ 1)

The equation of an aline in point-slope form

The equation of an aline in point-slope form is expressed as:

y - y 1 = m(x-x1)

m is the slope

(x1, y1) is any point on the line

Given the following

(x1, y1) = (-1, -1)

m = 3+3/2+0
m = 6/2
m = 3

Substitute into the formula

y - (-1) = 3(x-(-1))
y + 1  = 3(x+ 1)

Hence the equation, in the point-slope form of the line the parallel to the given line and passes through the point (-1,-1) is y + 1  = 3(x+ 1)

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