contestada

Two actors who are pretending to be ninjas are flying toward each other with the help of wires. pretend ninja number one is flying at 10 ft./s and pretend ninja number two is flying at 12 feet per second if the two are 88 feet apart how many second will it be before they collide

Respuesta :

Answer:

It'll take them 7.334 s to collide.

Step-by-step explanation:

Since the two ninjas are moving towards each other their relative speed is the sum of each individual speed, therefore:

[tex]v = 10 + 12 = 22 \text{ ft/s}[/tex]

Since they are a 88 feet apart, then we can calculate the time it'll take them to hit each other is:

[tex]\Delta S = v*t[/tex]

[tex]t = \frac{\Delta S}{v}[/tex]

Applying the data from the problem, we have:

[tex]t = \frac{88}{12} = 7.334 \text{ s}[/tex]

It'll take them 7.334 s to collide.

Otras preguntas