If 5.9 × 10²⁵ molecules of CO₂ are produced in a combustion reaction, how many liters of CO₂ is produced? (The density of CO₂ is 1.98 kg/m³ and 1 L = 1 dm³).

Respuesta :

Answer:

2.18 × 10³L

Explanation:

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2178 litres of CO2 is produced in the combustion reaction.

HOW TO CALCULATE VOLUME

  • The volume of a substance can be calculated using the formula below:

Density = mass ÷ volume

  • Firstly, we must calculate the number of moles present in 5.9 × 10²⁵ molecules by dividing by Avogadro number:

no of moles. = 5.9 × 10²⁵ ÷ 6.02 × 10²³

no. of moles = 5.9/6.02 × 10²

no. of moles = 0.98 × 10²moles

= 98moles

Moles = mass ÷ molar mass

Mass of CO2 = moles × molar mass

Molar mass of CO2 = 12 + 16(2) = 44g/mol

Mass of CO2 = 98 × 44

Mass of CO2 = 4312g = 4.312kg

  • The volume of CO2 can be calculated as follows:

Volume = 4.312kg ÷ 1.98kg/m³

Volume = 2.178m³

Since 1m³ = 1000L

2.178m³ = 2.178 × 1000

= 2178 liters.

  • Hence, 2178 litres of CO2 is produced in the combustion reaction.

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