Respuesta :
Answer:
Step-by-step explanation:
Given functions are
y = 5 cos ( 2π / 3 ) t
y = 5 cos ( 4π / 3 ) t
y= 10 cos ( 2π / 3 ) t
y = 10 cos ( 4π / 3 ) t
The pendulum half oscillation from left extreme to right extreme takes 1.5 s
So its time period of oscillation T = 1.5 x 2 = 3 s .
standard equation of oscillation is
y = A cos ω t where A is amplitude and ω is angular frequency .
Amplitude of oscillation A = 10 / 2 = 5 inch .
Among the given equation of motion only first two has amplitude equal to 5 . So both the last two are ruled out .
The angular frequency of first motion as per given equation
ω = 2π / 3
If time period is T
2π / T = 2π / 3
T = 3 s
So it matches with the time period of oscillation of pendulum .
Hence the first equation truly represents the oscillation of pendulum.
The function models the horizontal displacement as a function of time in seconds is [tex]\rm y = 10 sin(\dfrac{2\pi}{3})t[/tex] and this can be determined by using the given data.
Given :
It takes 1.5 seconds for a grandfather clock's pendulum to swing from left (initial position) to right, covering a horizontal distance of 10 inches.
For the oscillation the standard equation is given below:
[tex]\rm y = A\;cos \;\omega t[/tex]
where A is the amplitude, [tex]\omega[/tex] is the angular velocity, and t is the time.
Now, determine the time period that is:
T = 1.5 [tex]\times[/tex] 2
T = 3sec
Now, the angular frequency is given by:
[tex]\omega = \dfrac{2\pi}{3}[/tex]
So, the function models the horizontal displacement as a function of time in seconds is given below:
[tex]\rm y = 10 sin(\dfrac{2\pi}{3})t[/tex]
Therefore, the correct option is C).
For more information, refer to the link given below:
https://brainly.com/question/40973
