Probability a bag of miniature candy’s contain 15 crunch bars 14 Hershey’s chocolate bars 10 Mr.Goodbars 12 Hershey’s cookies and cream bars. What is the probability of randomly choosing each of them ?

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Brodge

15:51 for Crunch bars

14:51 for Hershey's

10:51 for Mr. Goodbars

12:51 for Cookies and Cream

There are 51 candies in total. We got that by adding all of the candies together. 15 + 14 + 10 + 12 = 51. The probability can be written as a ratio between the different types of candy and the whole number.

The probability of crunch bars, Hershey’s chocolate bars, Mr.Goodbars, and Hershey’s cookies and cream bars are 15/51, 14/51, 10/51, and 12/51, respectively.

What is Probability?

Probability helps us to know the chances of an event occurring.

[tex]\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}[/tex]

The probability can be written as,

P(Crunch bars) = Number of Crunch bars/ Total number of choclates= 15/51

P(Hershey's Chocolate) = 14/51

P(Mr. Goodbars) = 10/51

P(Hershey’s cookies and cream bars) = 12/51

Hence, the probability of crunch bars, Hershey’s chocolate bars, Mr.Goodbars, and Hershey’s cookies and cream bars are 15/51, 14/51, 10/51, and 12/51, respectively.

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