Answer:
[tex] \huge{ \bold{ \boxed{ \tt{x = 11}}}}[/tex]
Step-by-step explanation:
[tex] \text{ - 10x + 17x - 2 = 5(x + 4)}[/tex]
Subtract 10x from 17x
10x and 17x are like terms. So, the coefficients of like terms can be added or subtracted.
[tex] \dashrightarrow{ \sf{ 7x - 2 = 5(x + 4)}}[/tex]
Distribute 5 through the parentheses
[tex] \dashrightarrow{ \sf{7x - 2 = 5 \times x + 5 \times 4}}[/tex]
[tex] \dashrightarrow{ \sf{7x - 2 = 5x + 20}}[/tex]
Move 5x to left hand side ( L.H.S ) and change it's sign
Similarly , move 2 to right hand side ( R.H.S ) and change it's sign
[tex] \dashrightarrow{ \sf{7x - 5x = 20 + 2}}[/tex]
Subtract 5x from 7x
[tex] \dashrightarrow{ \sf{2x = 20 + 2}}[/tex]
Add the numbers : 20 and 2
[tex] \dashrightarrow{ \sf{2x = 22}}[/tex]
Divide both sides by 2
[tex] \dashrightarrow{ \sf{ \frac{2x}{2} = \frac{22}{2}}} [/tex]
[tex] \dashrightarrow{ \boxed{ \sf{x = 11}}}[/tex]
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Now, let's check whether the value of x is 11 or not.
L.H.S = n[tex] \sf{ - 10x + 17x - 2}[/tex]
Plug the value of x and simplify
[tex] \longrightarrow{ \sf{ - 10 \times 11 + 17 \times 11 - 2}}[/tex]
[tex] \longrightarrow{ \sf{ - 110 + 187 - 2}}[/tex]
[tex] \longrightarrow{ \sf{77 - 2}}[/tex]
[tex] \dashrightarrow{ \sf{75}}[/tex]
R.H.S = [tex] \sf{5(x + 4)}[/tex]
plug the value of x and simplify
[tex] \longrightarrow{ \sf{5(11 + 4)}}[/tex]
[tex] \longrightarrow{ \sf{5 \times \: 15}}[/tex]
[tex] \longrightarrow{ \sf{75}}[/tex]
L.H.S = R.H.S
The value of x is 11 .
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Hope I helped!
Best regards :D
~[tex] \text{TheAnimeGirl}[/tex]
