Respuesta :
Answer:
5 sq. root 3
Explanation:
theta= 60°
=> u sin theta = 10 × sin 60
= 10× sq. root 3/2
= 5 sq. root 3
we have that from the Question"A projectile is launched at an angle of 60 degrees to the horizontal at an initial speed of 10 meters per second" it can be said that
the magnitude of the vertical component of its initial velocity is
- Fy=8.660N
From the Question we are told
A projectile is launched at an angle of 60 degrees to the horizontal at an initial speed of 10 meters per second. What is the magnitude of the vertical component of its initial velocity?
Generally the equation for vertical component is mathematically given as
The vertical component will be the resolution of the vertical axis
Therefore
Fy=10sin60
Fy=8.660N
Therefore
the magnitude of the vertical component of its initial velocity is
- Fy=8.660N
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