A projectile is launched at an angle of 60 degrees to the horizontal at an initial speed of 10 meters per second. What is the magnitude of the vertical component of its initial velocity?

Respuesta :

Answer:

5 sq. root 3

Explanation:

theta= 60°

=> u sin theta = 10 × sin 60

= 10× sq. root 3/2

= 5 sq. root 3

we have that from the Question"A projectile is launched at an angle of 60 degrees to the horizontal at an initial speed of 10 meters per second" it can be said that  

the magnitude of the vertical component of its initial velocity is

  • Fy=8.660N

From the Question we are told

A projectile is launched at an angle of 60 degrees to the horizontal at an initial speed of 10 meters per second. What is the magnitude of the vertical component of its initial velocity?

Generally the equation for  vertical component is mathematically given as

The  vertical component will be the resolution of the vertical axis

Therefore

Fy=10sin60

Fy=8.660N

Therefore

the magnitude of the vertical component of its initial velocity is

  • Fy=8.660N

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