Answer:
The range is 15.15 m and the time in the air is 1.01 s
Explanation:
Horizontal Motion
When an object is thrown horizontally (with angle 0°) with a speed v from a height h, it follows a curved path ruled exclusively by gravity until it eventually hits the ground.
The range or maximum horizontal distance traveled by the object can be calculated as follows:
[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]
To calculate the time the object takes to hit the ground, we use the equation below:
[tex]\displaystyle t=\sqrt{\frac{2h}{g}}[/tex]
The cannon is shot from a height of h=5 m with an initial speed of v=15 m/s. The range is calculated below:
[tex]\displaystyle d=15\cdot\sqrt{\frac {2*5}{9.8}}=15*1.01[/tex]
d = 15.15 m
The time in the air is:
[tex]\displaystyle t=\sqrt{\frac{2*5}{9.8}}[/tex]
t = 1.01 s
The range is 15.15 m and the time in the air is 1.01 s
