Answer:
a = 1.49m/s²
Explanation:
Find the diagram attached
According to Newton's second law of motion
\sum Fx = ma
Fm - Ff = ma
Fm is the moving force
Ff is the frictional force
Fm = Wsin theta
Ff = μR = μWcos theta
Wsin theta - μWcos theta = ma
W is the weight = 50.1 * 9.8 = 490.98N
theta is the angle of inclination = 27.2°
μ is the coefficient of friction = 0.343
m is the mass = 50.1kg
a is the acceleration
Substitute into the formula as shown;
Wsin theta - μWcos theta = ma
490.98sin27.2° - 0.343(490.98)cos 27.2° = 50.1a
224.423 - 149.78 = 50.1a
74.64 = 50.1a
a = 74.64/50.1
a = 1.49m/s²
Hence the acceleration of the block is a = 1.49m/s²
