(a) The force required to stretch the spring is of 37.5 N.
(b) The work done on the spring is of 4.6775 J.
Given data:
The force constant of a spring is, k = 150 N/m.
The stretching distance of spring is, x = 0.25 m.
(a)
When some force is experienced on the spring, then due to this force then it will displace. Then, the expression for the force applied on the spring is given as,
[tex]F = k \times x[/tex]
Solve by substituting the values as,
[tex]F = 150 \times 0.25\\\\F = 37.5 \;\rm N[/tex]
Thus, we can conclude that the force required to stretch the spring is of 37.5 N.
(b)
And the expression for the work done on the spring is given as,
[tex]W = \dfrac{1}{2}kx^{2}[/tex]
Solving as,
[tex]W = \dfrac{1}{2} \times 150 \times 0.25^{2}\\\\W = 4.6875 \;\rm J[/tex]
Thus, we can conclude that the work done on the spring is of 4.6775 J.
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