What is the value of x if HF = 4x+1 and AB = 12x-3?|
Given m

Answer: x = 1.25
Step-by-step explanation:
HF - is the middle line of the triangle ABC.
[tex]HF=\dfrac{1}{2} AB\\\\HF=4x+1\\AB=12x-3\\\\4x+1=\dfrac{1}{2} \cdot (12x-3)\\\\4x+1=\dfrac{12x-3}{2} \\\\(4x+1) \cdot 2 =12x-3\\8x+2=12x-3\\8x+2-12x=12x-3-12x\\-4x+2=-3\\-4x+2-2=-3-2\\-4x=-5\\-4x \cdot (-1)=-5 \cdot (-1)\\4x=5\\4x \div 4=5 \div 4\\x=1.25[/tex]