A person walks first at a constant speed of 5.40 m/s along a straight line from point to point and then back along the line from to at a constant speed of 3.10 m/s. (a) What is her average speed over the entire trip

Respuesta :

Answer: The average speed over the entire trip is 3.94 m/s

Explanation:

As we know : [tex]speed=\frac{distance}{time}[/tex]

Let the distance of straight line from point to point be = d

Total distance covered = 2d

Time taken to cover the forward journey = [tex]\frac{d}{5.40}[/tex]

Time taken to cover the backward journey = [tex]\frac{d}{3.10}[/tex]

Total time for the journey = Time taken to cover the forward journey  + Time taken to cover the backward journey  = [tex]\frac{d}{5.40}+\frac{d}{3.10}[/tex]

Average speed = [tex]\frac{\text {total distance}}{\text {total time}}=\frac{2d}{\frac{d}{5.40}+\frac{d}{3.10}}=3.94m/s[/tex]

Thus  average speed over the entire trip is 3.94 m/s