Respuesta :

Space

Answer:

0.0113 mol Ba(ClO₃)₂

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structures

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

Step 1: Define

3.45 g Ba(ClO₃)₂

Step 2: Identify Conversions

Molar Mass of Ba - 137.33 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Ba(ClO₃)₂ - 137.33 + 2(35.45) + 6(16.00) = 304.33 g/mol

Step 3: Convert

  1. Set up:                              [tex]\displaystyle 3.45 \ g \ Ba(ClO_3)_2(\frac{1 \ mol \ Ba(ClO_3)_2}{304.33 \ g \ Ba(ClO_3)_2})[/tex]
  2. Multiply/Divide:                [tex]\displaystyle 0.011336 \ mol \ Ba(ClO_3)_2[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.011336 mol Ba(ClO₃)₂ ≈ 0.0113 mol Ba(ClO₃)₂

Otras preguntas