1). what is the area of the rectangle whose length is (x+5) and width (x-5)?
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Answer:
[tex]x^{2}[/tex]-25
Step-by-step explanation:
formula for areas of rectangles= width x height
width=x-5
height=x+5
(x-5)(x+5)= [tex]x^{2}[/tex]-5x+5x-25
since the 5x's cancel out each other
=[tex]x^{2}[/tex]-25 will be the answer
The area of rectangle is [tex](x^{2} -25)[/tex] unit square.
The area of rectangle is product of length and width.
[tex]Area = length*width[/tex]
Given that length is [tex](x+5)[/tex] and width is [tex](x-5)[/tex].
[tex]Area=(x+5)*(x-5)\\\\Area=x^{2} -5x+5x-25=x^{2} -25[/tex]
Hence, the area of rectangle is [tex](x^{2} -25)[/tex] unit square.
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