Answer:
[tex]\sqrt{\left(x^2-y^2\right)^2+\left(2xy\right)^2}[/tex]
Step-by-step explanation:
Hypotenuse of a right triangle can be found using the Pythagorean theorem which states that both legs squared and added is equal to the hypotenuse squared. In other words, if A and B are legs and C is the hypotenuse:
[tex]C=\sqrt{A^2+B^2}[/tex]
We are told that one of the legs is [tex]x^2-y^2[/tex] and the other is [tex]2xy[/tex] so we get [tex]\sqrt{\left(x^2-y^2\right)^2+\left(2xy\right)^2}[/tex] when we substitute the legs into the formula presented above.
