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You must first get the equation in slope-intercept form. y-3=1/2(x+3) First, distribute the 1/2 to the x and 3 Your equation should look like this: y-3=1/2x+1.5 Next, add the three to both sides of the equation. Your equation should look like this: y=1/2x+4.5 To graph, you must determine your y-intercept and slope values. 1/2 is the slope value and 4.5 is the y-intercept. First plot the y-intercept at the point (0, 4.5). Next, go down one whole unit and then left 2 whole units. This point should be (-2, 3.5). Repeat this process until the equation's line extends all the way to the ends of the graph. To plot the points going up, go up one whole unit and then right two whole units. This point should be (2, 5.5). Good luck!! Hope this helped :3

Answer:

Given : Equation  [tex]y-3=\frac{1}{2}(x+3)[/tex]

To plot : The graph of the equation.

Solution :  

We need two points to graph a straight line.

The x- and y-intercepts are easiest to find by putting x and y equal to zero

Put x=0 in the given equation,

[tex]y-3=\frac{1}{2}(x+3)[/tex]

[tex]y-3=\frac{1}{2}(0+3)[/tex]

[tex]y=\frac{3}{2}+3[/tex]

[tex]y=\frac{9}{2}[/tex]

[tex]y=4.5[/tex]

We get a point (0,4.5)

Now, Put y=0 in the given equation,

[tex]y-3=\frac{1}{2}(x+3)[/tex]

[tex]0-3=\frac{1}{2}(x+3)[/tex]

[tex]-6=x+3[/tex]

[tex]x=-6-3[/tex]

[tex]x=-9[/tex]

We get a point (-9,0)

We get two points so, plot these two points and form a linear line.

The line formed is the required graph of the equation.

Refer the attached figure.

Ver imagen tardymanchester

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