Respuesta :
Answer:
a) the power loss due to irreversible head loss is 4.57 kW
b) the efficiency of the piping is 95%
c) the electric power output is 72.9918 kW
Explanation:
Given the data in the question below;
Irreversible loses [tex]h_L[/tex] = 7m
Total head, H = 140 m
flow rate Q = 4000 L/min = 0.0666 m³/s
Generator efficiency n₀ = 84% = 0.84
we know that density of water is 1000 kg/m³
g = 9.81 m/s²
a) power loss due to irreversible head loss [tex]P_L[/tex] is;
[tex]P_L[/tex] = p × Q × g × [tex]h_L[/tex]
we substitute
[tex]P_L[/tex] = 1000 × 0.0666 × 9.81 × 7
[tex]P_L[/tex] = 4573.422 W
[tex]P_L[/tex] = 4573.422 / 1000
[tex]P_L[/tex] = 4.57 kW
Therefore, the power loss due to irreversible head loss is 4.57 kW
b) the efficiency of the piping n is;
n = (Actual head / maximum head) × 100
n = (( H - [tex]h_L[/tex] ) / H) × 100
so we substitute
n = (( 140 - 7 ) / 140) × 100
n = (133/140) × 100
n = 0.95 × 100
n = 95%
Therefore, the efficiency of the piping is 95%
c) the electric power output if the turbine-generator efficiency is 84 percent;
n₀ = [tex]Power_{outpu[/tex] / [tex]power_{inpu[/tex]
[tex]Power_{outpu[/tex] = n₀ × [tex]power_{inpu[/tex]
[tex]Power_{outpu[/tex] = n₀ × ( pQg( H - [tex]h_L[/tex] ))
so we substitute
[tex]Power_{outpu[/tex] = 0.84 × ( 1000 × 0.0666 × 9.81( 140 - 7 ))
[tex]Power_{outpu[/tex] = 0.84 × 653.346( 133)
[tex]Power_{outpu[/tex] = 0.84 × 86895.018
[tex]Power_{outpu[/tex] = 72991.815 W
[tex]Power_{outpu[/tex] = 72991.815 / 1000
[tex]Power_{outpu[/tex] = 72.9918 kW
Therefore, the electric power output is 72.9918 kW