Answer:
[tex] x = - 1 + 2i, \: \: - 1 - 2i[/tex]
Step-by-step explanation:
[tex] {x}^{2} + 2x + 5 = 0 \\ \\ {x}^{2} + 2x + 1 + 4 = 0 \\ \\ {x}^{2} + 2x + 1 = - 4 \\ \\ {(x + 1)}^{2} = - 4 \\ \\ (x + 1) = \pm \sqrt{ - 4} \\ \\ x + 1 = \pm 2i \\ \\ x = - 1\pm 2i \\ \\ x = - 1 + 2i, \: \: x = - 1 - 2i \\ \\ x = - 1 + 2i, \: \: - 1 - 2i[/tex]