Answer:
a) 156 meters
b) 58 m/s
c) 9.8 m/s^2
Explanation:
a) The horizontal displacement X = V *t
X = 50 * 3 = 150 meters
Vertical displacement = y = – g * t² / 2
Y = -9.8 *3*3/2 = -4.9*9 = 44.1
Net Displacement = Sqrt (X^2 +Y^2) = 156.34 = 156 meters
b) Speed of the projectile
vx = 50 m/s
vy = t*g = 9.8*3 = 29.4
V = Sqrt (vx^2 + vy^2) = 58 m/s
c) Acceleration is the acceleration due to gravity = 9.8 m/s^2
The magnitude of the displacement of the projectile is equal to 156 meters.
Given the following data:
Scientific data:
Mathematically, the magnitude of the displacement of a projectile is given by this formula:
[tex]Horizontal\;displacement = Vt\\\\Horizontal\;displacement = 50.0 \times 3.00[/tex]
Horizontal displacement = 150.0 meters.
[tex]Vertical displacement =\frac{1}{2} gt^2\\\\Vertical displacement =\frac{1}{2} \times 9.8 \times 3^2\\\\Vertical displacement =\frac{1}{2} \times 9.8 \times 9[/tex]
Vertical displacement = 44.1 meters.
[tex]D^2 = X^2 +Y^2\\\\D =\sqrt{44.1^2+150^2}[/tex]
D = 156.34 ≈ 156 meters.
b. For the speed of the projectile:
Vertical speed = tg
[tex]V_y = tg = 9.8\times3\\\\ V_y = 29.4\;m/s[/tex]
[tex]D^2 = V_x^2 +V_y^2\\\\D =\sqrt{50^2+29.4^2}[/tex]
D = 58 m/s.
c) The magnitude of the acceleration of the projectile is equal to the acceleration due to gravity ([tex]9.8 \;m/s^2[/tex]).
Read more on acceleration here: brainly.com/question/247283
