Respuesta :
The solution to the problem is as follows:
First thing to do is get rid of the i. Multiplying by 6 - 2i will do this
( 6 + 2i)(6 - 2i) = 6^2 - (2i)^2 = 36 - 4(-1) = 36 + 4 = 40
Dividing by 40 gets you 1
(6 + 2i) (6-2i)/40 = 1
The answer is (6 - 2i)/40 = (3 - i)/20
I hope my answer has come to your help. God bless and have a nice day ahead!
First thing to do is get rid of the i. Multiplying by 6 - 2i will do this
( 6 + 2i)(6 - 2i) = 6^2 - (2i)^2 = 36 - 4(-1) = 36 + 4 = 40
Dividing by 40 gets you 1
(6 + 2i) (6-2i)/40 = 1
The answer is (6 - 2i)/40 = (3 - i)/20
I hope my answer has come to your help. God bless and have a nice day ahead!
SOS
Answer:
[tex]\frac{3}{20}-\frac{1}{20}i[/tex]
Step-by-step explanation:
Find the multiplicative inverse of a complex number using the process described below:
The inverse is found by reciprocating the original complex number. The reciprocal of the complex number (6+2i) is [tex]\frac{1}{6+2i}[/tex]. Multiply the numerator and denominator of the reciprocal by conjugate of the denominator and simplify:
[tex]\frac{1}{6+2i}*\frac{6-2i}{6-2i}[/tex]
You get: [tex]\frac{3}{20}-\frac{1}{20}i[/tex]
Hope this helps!!