Answer:
[tex]\frac{-27b^{6}}{c^{18}}[/tex]
Step-by-step explanation:
first distribute the ^3, -3^3=-27, for the variables, (x^y)^3=x^(3y) so (b^2)^3=b^6 and (c^-6)^3=c^-18. now we have [tex]-27b^{6}c^{-18}[/tex]. Next we have to get rid of the negative in c^-18. x^-y=1/x^y so c^-18=[tex]\frac{1}{c^{18}}[/tex], plug it in and you get [tex]\frac{-27b^{6}}{c^{18}}[/tex]
