An elliptical of the satellite in the field of astrodynamics is known as a
Kepler orbit.
The distance between the satellite and the Earth is; 510 km.
Reasons:
The function that represents the elliptical orbit of the satellite is presented
as follows;
[tex]\dfrac{x^2}{47,334,400} + \dfrac{y^2}{43,956,900} = 1[/tex]
The radius of the Earth, R = 6,370 km.
The equation of an ellipse is presented as follows;
[tex]\mathbf{\dfrac{(x - h)^2}{a^2} + \dfrac{(y - k)^2}{b^2}} = 1[/tex]
Where, in a horizontal ellipse;
a = The major axis (the longer axis), which gives the maximum distance
between the satellite and Earth.
b = The minor axis (the shorter axis)
By comparison, we get;
a² = 47,334,400 km²
Therefore;
a = √(47,334,400 km²) = 6,880 km.
The distance between the satellite and the surface of the Earth, d, is given
as follows;
d = a - R
Which gives;
d = 6,880 km - 6,370 km = 510 km
Distance between the satellite and the surface of the Earth, d = 510 km.
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