A satellite orbits the Earth with an elliptical orbit modeled by x squared over 47 million three hundred thirty four thousand four hundred plus y squared over forty three million nine hundred fifty six thousand nine hundred equals 1 comma where the distances are measured in km. The Earth shares the same center as the orbit. If the radius of the Earth is 6,370 km, what is the maximum distance between the satellite and the Earth?

6,880 km
6,630 km
510 km
260 km

Respuesta :

An elliptical of the satellite in the field of astrodynamics is known as a

Kepler orbit.

The distance between the satellite and the Earth is; 510 km.

Reasons:

The function that represents the elliptical orbit of the satellite is presented

as follows;

[tex]\dfrac{x^2}{47,334,400} + \dfrac{y^2}{43,956,900} = 1[/tex]

The radius of the Earth, R = 6,370 km.

The equation of an ellipse is presented as follows;

[tex]\mathbf{\dfrac{(x - h)^2}{a^2} + \dfrac{(y - k)^2}{b^2}} = 1[/tex]

Where, in a horizontal ellipse;

a = The major axis (the longer axis), which gives the maximum distance

between the satellite and Earth.

b = The minor axis (the shorter axis)

By comparison, we get;

a² = 47,334,400 km²

Therefore;

a = √(47,334,400 km²) = 6,880 km.

The distance between the satellite and the surface of the Earth, d, is given

as follows;

d = a - R

Which gives;

d = 6,880 km - 6,370 km = 510 km

Distance between the satellite and the surface of the Earth, d = 510 km.

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