Answer:
19/23, 50/23
Step-by-step explanation:
We can take the first equation and isolate the x:
x + 5y = 3 ⇒ -5y ⇒
x = 3 - 5y.
Then we can substitute the x in the first equation by this:
3y + 2 = 4(3-5y) ⇒
3y + 2 = 12 - 20y ⇒ +20y
23y + 2 = 12 ⇒ -2
23y = 10 ⇒ ÷23
y = [tex]\frac{10}{23}[/tex]
Then we can add the value of y into the equation equaling x we made:
x = 3 - 5([tex]\frac{10}{23}[/tex]) ⇒
x = 3 - [tex]\frac{50}{23}[/tex] ⇒
x = [tex]\frac{19}{23}[/tex]
Hope this helps! :)
