The inequality which represents the constraints of the range is D. p(m) ≥ -875
Since the PTA was doing fundraiser and bought 500 megaphones to sell for the pep rally, and the profit, p, from the sale of megaphones can be represented by p(m) = 3.5m - 875 where m = number of megaphones sold.
To find the inequalities represents the constraints of the range of p(m), we need to know the domain of m.
Since we have 500 megaphones and we can sell from 0 to 500 inclusive. So, the domain of m is 0 ≤ m ≤ 500.
To determine the range of p(m), we insert the values of m at its extreme points into p(m).
So, when m = 0
p(m) = 3.5m - 875
p(0) = 3.5(0) - 875
p(0) = 0 - 875
p(0) = -875
when m = 500
p(m) = 3.5m - 875
p(500) = 3.5(500) - 875
p(500) = 1750 - 875
p(500) = 875
Since for a profit, m ≥ 0. So, p(m) ≥ p(0) = -875
So, p(m) ≥ -875
So, the inequality which represents the constraints of the range is D. p(m) ≥ -875
Learn more about inequalities here:
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