Answer:
125
Step-by-step explanation:
[tex] \huge \: {8}^{ log_{2}(5) } \\ \\ \huge \: = { {2}^{3} }^{ log_{2}(5) } \\ \\ \huge \: = { {2}}^{ log_{2}(5)^{3} } \\ \\\huge \: ={ {2}}^{ log_{2}(125 )} \\ \\ \huge \: = 125 \: \: ( \because \: {a}^{ log_{a}(x)} =x)[/tex]
