Answer:
Step-by-step explanation:
a = 5, b = -7 c = 1
[tex]x=\frac{-b\pm\sqrt{{b^2-4ac}}}{2a}\\=\frac{-(-7)\pm\sqrt{{(-7)^2-4(5)(1)}}}{2(5)}\\\\=\frac{{7}\pm\sqrt{{49-20}}}{10}\\\\\\=\frac{{7}\pm\sqrt{{29}}}{10}\\\\[/tex]
so
[tex]x_1=\frac{7+\sqrt{29}}{10}\\x_2=\frac{7-\sqrt{29}}{10}[/tex]
